x^2+4x-8=x^2+1x+4

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Solution for x^2+4x-8=x^2+1x+4 equation:


Simplifying
x2 + 4x + -8 = x2 + 1x + 4

Reorder the terms:
-8 + 4x + x2 = x2 + 1x + 4

Reorder the terms:
-8 + 4x + x2 = 4 + 1x + x2

Add '-1x2' to each side of the equation.
-8 + 4x + x2 + -1x2 = 4 + 1x + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-8 + 4x + 0 = 4 + 1x + x2 + -1x2
-8 + 4x = 4 + 1x + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-8 + 4x = 4 + 1x + 0
-8 + 4x = 4 + 1x

Solving
-8 + 4x = 4 + 1x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1x' to each side of the equation.
-8 + 4x + -1x = 4 + 1x + -1x

Combine like terms: 4x + -1x = 3x
-8 + 3x = 4 + 1x + -1x

Combine like terms: 1x + -1x = 0
-8 + 3x = 4 + 0
-8 + 3x = 4

Add '8' to each side of the equation.
-8 + 8 + 3x = 4 + 8

Combine like terms: -8 + 8 = 0
0 + 3x = 4 + 8
3x = 4 + 8

Combine like terms: 4 + 8 = 12
3x = 12

Divide each side by '3'.
x = 4

Simplifying
x = 4

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